Math, asked by rekhashashi5397, 9 months ago

Find the value of squarerootof15+8i+squareroot of15-8i​

Answers

Answered by brainliest2008
0

Answer:

Step-by-step explanation:

Assume  −15−8i−−−−−−−√=(a+ib) .

⇒(a+ib)2=−15−8i  

⇒a2+i2b2+2iab=−15−8i  

⇒a2−b2+2iab=−15−8i  

⇒ab=−4;a2−b2=−15  

Now,  ⇒a2−(−4a)2=−15  

⇒a2−16a2=−15  

⇒a4+15a2−16=0  

⇒a=±4,a=1  

Now,  b=−4a=−4±4=±1  

Therefore,  −15−8i−−−−−−−√=±(4−i)

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Answered by kgigheesh
0

Answer:

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