Find the value of squarerootof15+8i+squareroot of15-8i
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Assume −15−8i−−−−−−−√=(a+ib) .
⇒(a+ib)2=−15−8i
⇒a2+i2b2+2iab=−15−8i
⇒a2−b2+2iab=−15−8i
⇒ab=−4;a2−b2=−15
Now, ⇒a2−(−4a)2=−15
⇒a2−16a2=−15
⇒a4+15a2−16=0
⇒a=±4,a=1
Now, b=−4a=−4±4=±1
Therefore, −15−8i−−−−−−−√=±(4−i)
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