Question

Find the value of such that the polynomial x^2 −k ( k+ 6)x + 2(2k − 1) has sum of its zeros equal to half of their product

Answer 1

ANSWER

K = -2 +√3

CONCEPT

• USE GIVEN RELATION
• QUADRATIC FORMULA

EXPLANATION

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Answer 2

Answer:

solved

Step-by-step explanation:

x^2 −k ( k+ 6)x + 2(2k − 1) = 0

x² −k ( k+ 6)x + 2(2k − 1) = 0

k ( k+ 6) = 2k − 1

k²+4k+1=0

k = -4±√12÷2

k = -2±√3