find the value of α such that the quadratic equation (α-3)xsquare + 4(α-3)x + 4=0 has equal roots
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if roots are equal then D=0
16(a-3)^2-4(a-3)(4)=0
(a-3)[16(a-3) - 16]=0
(a-3)(16a-48-16)=0
so either a-3=0 ; a=3
or 16a -64=0 ; a=4
16(a-3)^2-4(a-3)(4)=0
(a-3)[16(a-3) - 16]=0
(a-3)(16a-48-16)=0
so either a-3=0 ; a=3
or 16a -64=0 ; a=4
hardiksoni16289:
it is Alpha not a
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0
Answer:
alpha=3,4
Step-by-step explanation:
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