Question

Find the value of t if the value of 3x2 + 5x – 2t = 8, when x = -1.​

Answer 1

Answer:

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Step-by-step explanation:

$3x²+5x-2t = 8 \\ \\ 3( - 1) {}^{2} + 5( - 1) - 2t = 8 \\ \\ 3(1) + 5( - 1) - 2t = 8 \\ \\ 3 - 5 - 2t = 8 \\ \\ 2t = 3 -5 - 8 \\ \\ 2t = - 10 \\ \\ t = \frac{ - 10}{2} \\ \\ t = -5$

Verification

$3x^2+5x-2t=8 \\ \\putting \:\: t = -5\: \:and \:\:x = -1 \:\:in\: \:LHS \:\:of\:\: the \:\:equation\\ \\3(-1)^2+5(-1)-2(-5)\\ \\3(1)+5(1)-2(-5)\\ \\3-5+10\\ \\-2+10\\ \\8\\ \\= RHS$

Hence verified that t = -5

Answer 2

Answer:

$x = - 1 \\ \\ 3 {x}^{2} + 5x - 2t = 8 \\ 3 {( - 1)}^{2} + (5 \times - 1) - 2t = 8 \\ (3 \times 1) + ( - 5) - 2t = 8 \\ 3 - 5 - 2t = 8 \\ - 2 - 2t = 8 \\ - 2 - 8 = 2t \\ -10 = 2t \\ \frac{ - 10}{2} = t \\ \large{ \boxed{\underline{ \underline{- 5}} = t}}$