find the value of t so that (10)^-2×(10)^-9=10^2t+1
Tell me the answer correctly please. And fast.
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Answer:
t= -6
Step-by-step explanation:
10^-2×10^-9=10^2t+1
a^m×a^n=a^m+n
10^-2×10^-9=10^2t+1
10^-2+(-9)=10^2t+1
10^-11=10^2t+1
since bases are same, equate the powers
-11=2t+1
2t= -11-1
2t= -12
t= -12/2
t= -6
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