Question

find the value of t5 for an ap 8,6,4...?​

Answer 1

Answer:

we know that

a+(n-1)d=an

a=8

d=6-8=-2

n=5

So

8+(5-1)(-2)

8+4×(-2)

8-8

=0

Answer 2

Answer:

The correct answer of this question is  t5 = 0

Step-by-step explanation:

Given - The value of t5 for an ap 8,6,4...

To Find - Find the value of t5 for an ap 8,6,4...

The difference between the previous and subsequent terms may be used to  compute the common difference for any A.P.

The n-th term of an A.P. with the initial term a and the common difference d may be written as;n-th term of the A.P.= An = a + (n-1)d

The first term of the given A.P. = a = 8

The common difference of the given $A.P.$ = $d$

= (second term) - (first term)

= 6 - 8 = ( -2 )

The value of t5

= the value of the 5th term of the given A.P.

= $a + (5 - 1) d$

= $a + 4d$

= $8 + 4(-2)$

= $8 + (-8) = 8 - 8 = 0$

So, the value of t5 = 0

#SPJ2