Question

find the value of: tan 15 degree

Answer 1

tan15°=tan(45°-30°)
$tan(45°-30°)= \frac{tan45-tan30}{1+tan45.tan30} \\ \\ = \frac{1- \frac{1}{ \sqrt{3}} }{1+ \frac{1}{ \sqrt{3}} } \\ \\ =\frac{ \sqrt{3}-1}{ \sqrt{3} }/ \frac{ \sqrt{3}+1}{ \sqrt{3} }\\ \\ = \frac{ \sqrt{3}-1}{ \sqrt{3}+1} } \\ \\ = \frac{3-2 \sqrt{3} +1}{2} \\ \\ = \frac{4-2 \sqrt{3} }{2} \\ \\ =2- \sqrt{3}$

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Answer 2

hi....
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vlue of : tan15° = 0.2679

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Hope it will help u... ☺