Question

find the value of tan 15°​

Answer 1

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$\tan(15) = \frac{ \sin(15) }{ \cos(15) }$

$= \frac{ \sqrt{3} - 1 \div 2 \sqrt{2} }{ \sqrt{3} + 1 \div 2 \sqrt{2} } \\ = \frac{ \sqrt{3} - 1}{ \sqrt{3} + 1} \times \frac{ \sqrt{3} - 1}{ \sqrt{3} - 1 } \\ = \frac{3 - \sqrt{3} - \sqrt{3} + 1}{3 - 1} \\ = \frac{4 - 2 \sqrt{3} }{2} \\ = 2(2 - \sqrt{3} \div 2 \\ = 2 - \sqrt{3}$

Hope it helps you ❣️☑️

Answer 2

Answer:

the value of tan 15 degree is 2 - √3