Question

find the value of tan 15°​

Answer 1

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Answer 2

Answer:

$\tan(15) \\ \\ = \tan(45 - 30) \\ \\ = \frac{ \tan(45) - \tan(30) }{1 + \tan(45) \tan(30) } \\ \\ = \frac{1 - \frac{1}{ \sqrt{3} } }{1 + 1 \times \frac{1}{ \sqrt{3} } } \\ \\ = \frac{ \sqrt{3} - 1 }{ \sqrt{3} + 1} \\ \\ = 2 - \sqrt{3}$

hope this much helps uh ❣️