Math, asked by shahid2634, 11 months ago

find the value of tan^2 10 - cot^2 80​

Answers

Answered by shrutirajak
8

 { \tan}^{2} 10 -  {  \cot }^{2} 80 \\  { \tan }^{2} 10 -  {( \cot(90 - 10)) }^{2} \\  { \tan }^{2} 10 -  { \tan }^{2} 10 \\  = >  0

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