Math, asked by gsahu3145, 20 hours ago

Find the value of tan ²0 (1+Cot²o)​

Answers

Answered by 2013989
0

Answer:

sec^2

Step-by-step explanation:

= (sin^2/cos^2)(1+cos^2/sin^2)

= (sin^2/cos^2)(sin^2+cos^2/sin^2)

= (sin^2/cos^2)(1/sin^2)

( sin^2 will get cancelled)

=1/cos^2

=sec^2

Answered by manissaha129
0

Answer:

Formula used :

  • tan∅ = 1/cot∅
  • 1 + tan²∅ = sec²∅

 \longmapsto \tan {}^{2} ( \theta) (1 +  \cot {}^{2} ( \theta))  \\  =  \tan {}^{2} ( \theta)  +  \tan {}^{2} ( \theta) . \cot {}^{2} ( \theta)  \\  =  \tan {}^{2} ( \theta)  + 1 \\  = \boxed{ \sec {}^{2} ( \theta)}✓

  • tan²∅(1+cot²∅) = sec²∅ is the right answer.
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