find the value of tan 2A if cos 3A equals to sin 45
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Answered by
4
Given :
cos3A = sin45
=> cos3A = sin(90 - 45)
=> cos3A = cos45
So, 3A = 45, by inverting the cosine.
=> A = 15
So, we see that :
A = 15°
Now,
tan2A
= tan(2 × 15)°
= tan30°
= 1/(√3)
= 0.577 (approximately)
Remember :
sin(90 - θ) = cosθ
cos(90 - θ) = sinθ
tan(90 - θ) = cotθ
cot(90 - θ) = tanθ
sec(90 - θ) = cosecθ
cosec(90 - θ) = secθ
Answered by
1
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