find the value of tan 2A, if cos 3A =sin 45.
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Solution
==>Cos3A = sin 45
==>Sin ( 90 - 3A ) = sin 45
==>90 - 3A = 45
==>45 = 3A
==>A = 15
So, tan2A = tan 2x 15 = tan30 = 1 /√3h..
Thanks
Solution
==>Cos3A = sin 45
==>Sin ( 90 - 3A ) = sin 45
==>90 - 3A = 45
==>45 = 3A
==>A = 15
So, tan2A = tan 2x 15 = tan30 = 1 /√3h..
Thanks
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