find the value of tan (-330°) give me the steps
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chethansamanth1ygh:
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as 330 degree is 360-a it comes in 4 th quadrant
In 4 th quadrant only cos and sec are positive
so, tan(-330)= -tan(360-300)
= -tan(30)
= - (-1/root 3)
=1/root 3
I hope its right.
In 4 th quadrant only cos and sec are positive
so, tan(-330)= -tan(360-300)
= -tan(30)
= - (-1/root 3)
=1/root 3
I hope its right.
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