find the value of tan 40 + tan11 + tan 20 -tan 6 +tan 56.tan 11 + root 3 tan 40 tan 20
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60° = 40° + 20°
Taking “tan” on both sides,
tan 60° = tan(40° + 20°)
√3 = (tan 40° + tan 20°)/(1 – tan 40° tan 20°)
√3(1 – tan 40° tan 20°) = tan 40° + tan 20°
√3 – √3 tan 40° tan 20° = tan 40° + tan 20°
Therefore, tan 40° + tan 20° + √3 tan 40° tan 20° = √3
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