Question

Find the value of tan 45º + cot 45°.​

Answer 1

Answer:

i hope it is helpful to you

Step-by-step explanation:

Value of tan45° and cot45° is 1.

tanθ=sinθ/cosθ

Sin45=1/√ 2

Cos45=1/√ 2

tan45=sin45/cos45 =1

tan45°=1

:-Cot is the reciprocal of tan so cot45°=1.

Answer 2

$\bf{\underline{QUESTION:-}}$

Find the value of tan 45º + cot 45°

$\bf{\underline{SOLUTION:-}}$

$\sf tan 45° + cot 45°$

$\sf→ tan\theta + \frac{Sinθ 45°}{cos 45°}$--eq(¡)

we know,

• sin 45 ° = 1/√2
• cos 45° = 1/√2

Substituting in (1),

→ tan 45 = (1/√2) ÷ (1/√2)

→ 1/√2 x √2/1

→ (1x√2)/(√2x1) = 1

and,

→ cot 45 = 1/tan 45 = 1/1 = 1

→ tan 45 + cot 45 = 1+1 =2

→ tan 45 x cot 45 = 1 x 1 = 1

$\bf{\underline{Hence:-}}$

• tan 45º + cot 45° = 1