Find the value of :
tan 6° tan 66° tan 42° tan 78° ℅ ?
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Answered by
5
Given : tan6°tan42°tan66°tan78° = ?
Here we'll use the formula :
tan3x=(tanx)tan(60+x)tan(60-x)
Solution :-
[ ( tan6°tan66°tan54°)/ tan54°]*[(tan42°tan78°tan18°)/tan18°] =1
Therefore the answer is 1.
Hope this'll help you..!!
Answered by
6
Hmm, Good question :
See the attachment.
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