Find the value of tan 60° geometrically.
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3
value of tan 60 is
tanθ= sinθ/cosθ
sin60= √3/2
cos60= 1/2
tan60= √3/2/1/2
= √3/1
= √3
∴ value of tan 60 = √3
tanθ= sinθ/cosθ
sin60= √3/2
cos60= 1/2
tan60= √3/2/1/2
= √3/1
= √3
∴ value of tan 60 = √3
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Answer:
Step-by-step explanation:
draw AD ⊥ BC
ABD ≅ ACD
BD = DC BD = BC = a
and BAD = CAD BAD = CAD = 30o
Using Pythagoras theorem in ABD,
AD2 = AB2 - BD2
AD=√3a/2
tan 60=AD/DB=√3a/2/a/2=√3
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