Question

find the value of tan-cat(90'-0​

Answer 1

$tan A - cot(90-A)$

$= tan A - tan A$

$=0$

HOPE IT HELPS U

Answer 2

Correct Question:

Find the value of $\tt{tan \theta -cot(90- \theta)}$

Solution:

We know that, $\tt{tan \theta = cot(90- \theta)}$

Now, we can solve this question, either by two methods:

$\underline{\green{\sf{Method-1}}}$

$\tt{\longrightarrow tan \theta -cot(90- \theta)}$

$\tt{\longrightarrow cot(90- \theta) -cot(90- \theta)}$

On subtracting, we get the answer as:

$\longrightarrow\tt{0}$

$\underline{\green{\sf{Method-2}}}$

$\tt{\longrightarrow tan \theta -cot(90- \theta)}$

$\tt{\longrightarrow tan \theta -tan \theta}$

On subtracting, we get the answer as:

$\longrightarrow\tt{0}$

For both methods, the answer will be 0.

Know more:

$\tt{\longrightarrow sin \theta = cos(90- \theta)}$

$\tt{\longrightarrow cos \theta = sin(90- \theta)}$

$\tt{\longrightarrow tan \theta = cot(90- \theta)}$

$\tt{\longrightarrow cot \theta = tan(90- \theta)}$

$\tt{\longrightarrow sec \theta = cosec(90- \theta)}$

$\tt{\longrightarrow cosec \theta = sec(90- \theta)}$