Question

find the value of tan square 10°-cot square 80°​

Answer 1

I dont know these type of question because I am in class 8

Answer 2

$\tan^2 10^\circ-\cot^280^\circ=0$

Step-by-step explanation:

Given : Expression $\tan^2 10^\circ-\cot^280^\circ$

To find : The value of expression ?

Solution :

Expression $\tan^2 10^\circ-\cot^280^\circ$

Rewrite the expression as,

$=\tan^2(90-80)^\circ-\cot^2 80^\circ$

We know that, $\tan(90-\theta)=\cot\theta$

$=\cot^2(80)^\circ-\cot^2 80^\circ$

Subtracting them,

$=0$

Therefore, $\tan^2 10^\circ-\cot^280^\circ=0$

#Learn more

PROVE THAT :

Cos (90° - thita). Cos (90° - thita) = tan (90° - thita) / 1 + tan^2 (90°-thita)

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