find the value of tan theta + cot theta
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tan x + cot x=(sin²x+cos²x)/(sin x cos x)=1/(sin x cos x)
sin x+cos x=√2
Squaring it,
sin²x+cos²x+2sin x cos x=2
So, we can get sin x cos x from here and put it to get answer.
sin x+cos x=√2
Squaring it,
sin²x+cos²x+2sin x cos x=2
So, we can get sin x cos x from here and put it to get answer.
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Answer:
The value of tanθ + cotθ is 2.
Step-by-step explanation:
Given,
sinθ + cosθ = ---- (i)
we have to find,
tanθ + cotθ
⇒ sinθ/cosθ + cosθ/sinθ
⇒ sin²θ + cos²θ/(sinθcosθ) ---- (ii)
squaring both sides of equation (i), we get
sin²θ + cos²θ + 2( sinθcosθ ) = 2
⇒ 1 + 2( sinθcosθ ) = 2 ( trigonometric identities)
⇒ 2( sinθcosθ ) = 1
⇒ sinθcosθ = 1/2 ---- (iii)
Using equations (ii) and (iii), we get
tanθ + cotθ = 1/(1/2)
tanθ + cotθ = 2
Hence, the value of tanθ + cotθ is 2.
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