Math, asked by Akhileshsah, 9 months ago

Find the value of tan 'V3 - sec '(-2)​

Answers

Answered by adityaayushi2002
6

Answer:-π/3

Step-by-step explanation:

tan-1√3 - sec-1 (-2)

=tan-1√3-(π-sec-1 2)

=tan-1 tan π/3 -π+ sec-1sec π/3

=π/3-π+π/3

=-π/3

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