Find the value of tan x if sin x equal to 3 by 5 and x lies in the second quadrant
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Here, sin x = 3/5
As we know that sin x = P/H
so, P = 3 & H = 5.
We have to find out Value of B
By Pythagoras theorem,
B = √ H^2 - p^2
B = √ 25 - 9
B = 4
now tan x = P/B
= 3/4
But x in 2nd Quad. thatswhy tan x is negative in 2nd quad.
So your Final answer is
-3/4
As we know that sin x = P/H
so, P = 3 & H = 5.
We have to find out Value of B
By Pythagoras theorem,
B = √ H^2 - p^2
B = √ 25 - 9
B = 4
now tan x = P/B
= 3/4
But x in 2nd Quad. thatswhy tan x is negative in 2nd quad.
So your Final answer is
-3/4
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