Find the value of tan1°.tan2°.tan3°..........tan89°
Your options are A) 0
B) 1
C) 2
D) 1/2
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tan(90-1) tan(90-2).....tan45°
cot89 cot88..... tan45
cot89×tan89....1
1×1
the correct option is B.(1)
cot89 cot88..... tan45
cot89×tan89....1
1×1
the correct option is B.(1)
Answered by
8
tan1 tan 89 tan 2 tan 88.........tan 45
Here its odd terms so mid angle would be 45
And here by taking n th term from beginning and end
tan 1 tan(90-1) tan2 tan( 90-2)........tan45
tan 1 cot 1 tan 2 cot 2...........1
tan 1 × 1/tan1 × tan 2 × 1/tan2........
1 × 1×.....
1
Here its odd terms so mid angle would be 45
And here by taking n th term from beginning and end
tan 1 tan(90-1) tan2 tan( 90-2)........tan45
tan 1 cot 1 tan 2 cot 2...........1
tan 1 × 1/tan1 × tan 2 × 1/tan2........
1 × 1×.....
1
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