Find the value of tan15°
shajait:
tan 45=1
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tan15=tan(45-30)
=tan45 - tan30/1+tan45.tan30
=(1- 1/root(3))/1 + 1/root(3)
=root(3) -1/root(3)+1
Identity used :
tan(A-B)=tanA-tanB/1+tanA.tanB
Hope it helps you
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