Math, asked by kuldeepverma, 1 year ago

Find the value of tan15°​


shajait: tan 45=1
Anonymous: ___k off

Answers

Answered by Anonymous
6

tan15=tan(45-30)

=tan45 - tan30/1+tan45.tan30

=(1- 1/root(3))/1 + 1/root(3)

=root(3) -1/root(3)+1

Identity used :

tan(A-B)=tanA-tanB/1+tanA.tanB

Hope it helps you

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kuldeepverma: 2 root 3 hoga
Anonymous: this is right
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