find the value of tan2A if cos3A =sin45°
Kshitijraj:
sin45=cos45...so cos3a=cos45 which gives 3a=45 and a=15 putting a=15 in tan2A we get tan30 which is equal 1/root of 3!!
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Cos 3A = sin45
so, Cos 3A = sin (90-45)
Cos 3A = Cos45
so, 3A = 45
so, A = 15°
So, tan 2A = tan 2*15 = tan30° = 1/√3
so, Cos 3A = sin (90-45)
Cos 3A = Cos45
so, 3A = 45
so, A = 15°
So, tan 2A = tan 2*15 = tan30° = 1/√3
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here is the ans........
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