English, asked by jaswanth9361, 7 months ago

Find the value of

tan35 cot 78

cot 55 tan12

° °

+

° ° .

Answers

Answered by Anonymous

1

Answer:

Given,

cot55otan35o+tan12ocot78o

=cot(90o−35o)tan35o+tan(90o−78)cot78o

=tan35otan35o+cot78ocot78o as we know cot(90o−θ)=tanθ and tan(90o−θ)=cotθ

=1+1

=2

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