Question

Find the value of tan60 + sin 60 using trignometric table

Answer 1

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Answer 2

HEY MATE HERE IS YOUR ANSWER--

$\tan(60) = \sqrt{3 } \\ \\ \sin(60) = \frac{ \sqrt{3} }{2} \\ \\ \tan(60) + \sin(60) = \\ \\ \sqrt{3} + \frac{ \sqrt{3} }{2} = \\ \\ by \: taking \: lcm \: \\ \\ \frac{ \sqrt{3} + 2 \sqrt{3} }{2 } \\ \\ \frac{ {3} \sqrt{3} }{2}$

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