Question

Find the value of tan60°/sec60°+cosec60°​

Answer 1

Answer:

$tan60 {}^{0} = \frac{1}{ \sqrt{3} }$

$sec60 {}^{0} + cosec60 {}^{0} \\ = 2 + \frac{ 2 }{ \sqrt{3} }$

$= \frac{2 \sqrt{3 + 2} }{ \sqrt{3} }$

$= \frac{1}{ \sqrt{3} } \times \frac{ \sqrt{3} }{2 \sqrt{3 + 2} }$

$= \frac{1}{2 \sqrt{3 + 2} }$