Question

Find the value of tan60°-tan30°/1+tan60°-tan30°?

Answer 1

(Tan60-tan30)/(1+tan60-tan30)


{√3-1/√3}/{1+√3 -1/√3}

(3-1/√3)/{(√3+3-1)/√3}

2/√3+2

2/(2+√3)


I hope this will help you



-by ABHAY

Answer 2

(Tan60-tan30)/(1+tan60-tan30)

{√3-1/√3}/{1+√3 -1/√3}

(3-1/√3)/{(√3+3-1)/√3}

2/√3+2

2/(2+√3)