Question

Find the value of tangent and cosecant of angle which secant is 7

Answer 1

Answer:

Step-by-step explanation:

sec^2x-tan^2x=1

49-tan^2x=1

tan^2x=48

tanx=√48

cotx=1/√48

cosec^2x-cot^2=1

cosec^2x=1-1/48=47/48

cosecx=√(47/48)

Answer 2

Step-by-step explanation:

sec^2x-tan^2x=1

49-tan^2x=1

tan^2x=48

tanx=V48

cotx=1/√48

cosec^2x-cot^2=1

cosec^2x=1-1/48=47/48

cosecx=√(47/48)