Math, asked by manavmodi28gmailcom, 10 months ago

find the value of tanO×cot(90-O)+secO×cosec(90-O)+sin^2 75° + sin^15°÷tan20 tan40 tan45 tan50 tan70

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Answered by priyankarakesh28

2

Answer:

The value of the question is 2sec²O.

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