Question

Find the value of
$( {2}^{ - 1} \times {3}^{ - 1} ) \div {2}^{ - 3}$
plz.. expirts help me brainlist make plz... help
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Answer 1

Answer:

this is the answer

Answer 2

$\rm \: Answer :-$

$\bf \dfrac{4}{3}$

Step-by-step-Explaination :-

$( {2}^{ - 1} \times {3}^{ - 1} ) \div {2}^{ - 3}$

Now, We have to remember a property of Exponents. That is

${ \big \star} \: \: \rm {a}^{ - m} = {\huge(} \dfrac{1}{ {a}^{m} }{ \huge)}$

Now, by applying the law on the no.'s we get

${\huge[(} \dfrac{1}{2} { \huge)} \times {\huge(} \dfrac{1}{3} {\huge)]} \div { \huge(} \dfrac{1}{2} {\huge)} ^{3}$

Now , by multiply the third bracket portion we got

$\rm \hookrightarrow \: \dfrac{1}{6}\div \dfrac{1}{2 \times 2 \times 2}$

$\rm \hookrightarrow \: \dfrac{1}{6}\div \dfrac{1}{8}$

Now , by reciprocal we will remove the fraction of 8

$\rm \hookrightarrow \: \dfrac{1}{6} \times 8$

So, that becomes

$\rm \hookrightarrow \: \cancel\dfrac{8}{6}$

On simplifying ,

$\rm \hookrightarrow \bf\: \dfrac{4}{3}$