Math, asked by tanuburnwal, 10 months ago

find the value of
 ({2}^{ - 1}   \times  {4}^{ - 1})  \div  {2}^{ - 2}

Answers

Answered by BrainlyPopularman
1

Answer:

 \frac{ {2}^{ - 1}  \times  {4}^{ - 1} }{ {2}^{ - 2} }  =  {2}^{2 - 1}  \times  {4}^{ - 1}  = 2 \times  \frac{1}{4}  =  \frac{1}{2}  =  {2}^{ - 1}

Answered by Anonymous
0

Answer:

2

Step-by-step explanation:

(-2.-4)/4

8/4=2....... .................

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