Question

Find the value of
$( {3}^{0 } + {4}^{ - 1} ) \times {2}^{2}$



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Answer 1

1. Answer:

5

Step-by-step explanation:

${3}^{0} = 1 \\ {4}^{ - 1} = \frac{1}{4} \\ {2}^{2} = 4 \\ (1 + \frac{1}{4} ) \times 4 \\ (\frac{4 + 1}{4} ) \times 4 \\ \frac{5}{4} \times 4 = 5$