Question

find the value of
$a³+b \div a³b² + a²b² + b³a²$


Please solve this question..​

Answer 1

Answer:

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Answer 2

$\orange{\huge \tt \frac{ {a}^{3} {b}^{3} }{ {a}^{3} {b}^{2} + {a}^{2} {b}^{2} + {b}^{3} {a}^{2} } = {a}^{4} {b}^{3}a3b2+a2b2+b3a2a3b3=a4b3}$