Question

Find the value of :-
${cos}^{ - 1} (cos( \frac{3\pi}{8} ))$

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Answer 1

Step-by-step explanation:

${cos}^{ - 1} (cos( \frac{3\pi}{8} )) \\ \frac{3\pi}{8} is \: in \: the \: range \: of \: {cos}^{ - 1} \: which \: is \: closed \: intervals \: 0 \: to \: \pi \: so \\ {cos}^{ - 1} (cos \frac{3\pi}{8} ) = \frac{3\pi}{8}$

Answer 2

Answer:

cos

−1

(cos(

8

3π

))

8

3π

isintherangeofcos

−1

whichisclosedintervals0toπso

cos

−1

(cos

8

3π

)=

8

3π