Question

Find the value of

$i ^ 8 + 1 \div {i}^{3}$
​

Answer 1

Step-by-step explanation:

$\frac{ {i}^{8} + 1}{3}$

We know that

$i ^{2} = - 1 \\ {i}^{4} = { ({i}^{2} )}^{2} = 1 \\ i ^{8} = { ({i}^{4} )}^{2} = 1$

Given expression is

$\frac{1 + 1}{3} = \frac{2}{3}$