Question

Find the value of
$k$
for which the following equation has real roots :-
${x}^{2} - 4kx + k = 0$
​

Answer 1

Answer:

Here's your answer

if the following has real and equal roots

here

a= 1,b = 4k and c = k

D= b^2-4ac

D= 16k^2- 4k

So if the polynomial has real and equal roots...

D= 0

16k^2-4k=0

4k(4k-1) = 0..

So the value of k is

4k-1=0

k=1/4

Hope it helps ✌

Step-by-step explanation: