Math, asked by Anonymous, 1 year ago

Find the value of \mathsf{k} , for which the given equation has real roots :

\mathsf{\implies x^{2} \: + \: k( 4x \: + \: k \: - \: 1) \: + \: 2 \: = \: 0}


\textsf{Answer = k is any real number}

Answers

Answered by Hiteshbehera74
7
k > -1 OR k > ⅔
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Anonymous: Answer is given as -: k is any real number.
Brainlybarbiedoll: ye rational number nikli hai :thinking:
Answered by Anonymous
5
HEY THERE!!!


Refer To Attachment;)

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Anonymous: :)
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