Math, asked by vikas90948, 1 day ago

find the value of
p(y) = 2y {3} - 2y + 7for \: y =  - 2
please help ​

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Answered by mauryakusum045
1

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ANSWER \frac{1}{x^{2} - 3x + 6 }

ANSWER \frac{1}{x^{2} - 3x + 6 } x

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+6

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61 It is not quadratic polynomial.

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61 It is not quadratic polynomial.Explanation :

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61 It is not quadratic polynomial.Explanation :We know that,

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61 It is not quadratic polynomial.Explanation :We know that,In particular, for an expression to be a polynomial term, it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions.

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61 It is not quadratic polynomial.Explanation :We know that,In particular, for an expression to be a polynomial term, it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions.According to the question, that is not a polynomial.

ANSWER \frac{1}{x^{2} - 3x + 6 } x 2 −3x+61 It is not quadratic polynomial.Explanation :We know that,In particular, for an expression to be a polynomial term, it must contain no square roots of variables, no fractional or negative powers on the variables, and no variables in the denominators of any fractions.According to the question, that is not a polynomial.Because the variable is in the denominator as well as fractional expression.

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