Question

Find the value of :
$p(y) = 2y^{3} - 2y+\sqrt{7} for\: y = -2$​
answer fast please its urgent please help

Answer 1

Solution

Solve 3y(2y−7)−3(y−4)−63 for y=−2

First simplify it,

=6y

2

−21y−3y+12−63

=6y

2

−24y−51

Put y=−2

=6(−2)

2

−24(−2)−51

=6×4+48−51

6×4+48−51

24+48−51

=21

Answer 2

Answer:

22

Step-by-step explanation:

p(-2) = 22