Math, asked by lovelylava, 1 year ago

find the value of
 sin {}^{2} 1degree +sin  {}^{2} 3 degree + sin {}^{2} 5degree   + .... +  sin {}^{2} 87degree + sin {}^{2} 89 degree

Answers

Answered by Shardul27
0

 \:  \:  \:  \:   \:  { \sin}^{2}1degree  +  { \sin }^{2}3degree....... { \sin }^{2}87degree +  { \sin }^{2}89degree \\   = { \sin }^{2}1degree +  { \sin }^{2}3degree........ {  \sin}^{2}(90 - 3) +  {  \sin  }^{2}(90 - 1) \\  =  \sin ^{2} 1degree +  { \cos }^{2}1degree +  { \sin }^{2} 3degree +  { \cos}^{2}3degree + ......... \\  = 1 + 1.....45times \\  = 1 \times 45 \\  = 45.




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