Question

Find the value of
$\sin \frac{41\pi}{4}$
​

Answer 1

Solution:- We know that sine function is periodic with period 2π

$= \sin \frac{41\pi}{4}$

$= \sin(10\pi + \frac{\pi}{4} )$

$= \sin \frac{\pi}{4}$

$= \frac{1}{ \sqrt{2} }$

Give ❤️

Answer 2

Answer:

sin (10π + π/4)

sin π/4

sin 45°

1/√2