Find the value of
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Solution :
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We know that ,
i ) ( a + b )² - ( a - b )² = 4ab
ii ) ( a + b )² + ( a - b )² = 2( a² + b² )
iii ) a² - b² = ( a + b )( a - b )
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= [ (√3+1)²]² - [(√3-1)]²
= [(√3+1)² - (√3-1)²][(√3+1)² + (√3-1)² ]
= [4×(√3)×1] × { 2[(√3)² + 1²]}
= (4√3) × 2( 3 + 1 )
= (4√3) × 8
= 32√3
••••
********************************
We know that ,
i ) ( a + b )² - ( a - b )² = 4ab
ii ) ( a + b )² + ( a - b )² = 2( a² + b² )
iii ) a² - b² = ( a + b )( a - b )
*********************************
= [ (√3+1)²]² - [(√3-1)]²
= [(√3+1)² - (√3-1)²][(√3+1)² + (√3-1)² ]
= [4×(√3)×1] × { 2[(√3)² + 1²]}
= (4√3) × 2( 3 + 1 )
= (4√3) × 8
= 32√3
••••
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