Math, asked by kalasesharmila, 8 months ago

find the value of
$\sqrt{47089} + \sqrt{24336}$

Answers

Answered by sakshisingh27

1

**********************************************

Square root:

The square root of a number is that

number ,whose square is equal to the

given number.

*********************************************

Now , write the numbers 47089 and

24336 as product prime.

i ) 47089 = ( 7 × 7 ) × ( 31 × 31 )

Sqrt ( 47089 ) = 7 × 31 = 217

ii)24336 = ( 2 × 2 ) × ( 2 × 2 ) × ( 3 × 3 )

( 13 × 13 )

Sqrt ( 24336 ) = 2 × 2 × 3 × 13 = 156

Therefore ,

Sqrt ( 47089 ) + sqrt ( 24336 )

= 217 + 156

= 373

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Answered by Rohith200422

2

Question:

Find the value of :-

$\sqrt{47089}+ \sqrt{24336}$

To find:

★ To find the value of given expression.

Answer:

$The \: value \: is \: \underline{ \: \underline{ \: \sf \pink{ \bf373 } \: }\: }.$

Step-by-step explanation:

Now,

Finding L.C.M. ( Prime factorisation )

1. $\bold{47089}$

$\begin {array}{r | 1 } 7 & 47089 \\ \cline{2-2} 7 & 6727 \\ \cline{2-2} 7 & 6727 \\ \cline{2-2} 7 & 961 \\ \cline{2-2} 31 & 31 \\ \cline{2-2} & 1 \end {array}$

$47089 =7 \times 7 \times 31 \times 31$

$\sqrt{47089} = 7 \times 31$

$\boxed{ \sqrt{47089} = 217}$

2. $\bold{ 24336 }$

$\begin {array}{r | 1 } 2 & 24336 \\ \cline{2-2} 2 & 12168 \\ \cline{2-2} 2 & 6084 \\ \cline{2-2} 2 & 3042 \\ \cline{2-2} 2 & 1521 \\ \cline{2-2} 3 & 507 \\ \cline{2-2} 3 & 169 \\ \cline{2-2} 13 & 13 \\ \cline{2-2} & 1 \end {array}$

$24336 =2 \times 2 \times 2 \times 2 \times 3 \times 3 \times 13 \times 13$

$\sqrt{24336} = 2 \times 2 \times 3 \times 13$

$\boxed{ \sqrt{24336} = 156}$

Thus, $\sqrt{47089}+ \sqrt{24336}$

Now substituting the values,

$\implies 217 + 156$

$\implies \bf{373}$

$\therefore$ The value is 373 .

Test yourself:

$\bigstar \sqrt{77065} + \sqrt{56336}$

$\bigstar \sqrt{4589} + \sqrt{26746}$

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