Question

find the value of
$= \sqrt{48 } - \sqrt{72} - \sqrt{27} + 2 \sqrt{18}$
​

Answer 1

Answer:

$\sqrt{48} - \sqrt{72} - \sqrt{27} + 2 \sqrt{18}$

$4 \sqrt{3} - 6 \sqrt{2} - 3 \sqrt{3} + 6 \sqrt{2}$

$4\sqrt{3}-3\sqrt{3}$

$\sqrt{3}$