Math, asked by Divya6580, 1 month ago

find the value of
 \sqrt{5  + 2 \sqrt{6} }

Answers

Answered by XxYadavAshutoshxX
1

Answer:

\sf{\sqrt{3}+\sqrt{2}}

Explanation:

\sf{\sqrt{5+2\sqrt{6}}}can be written in the form \sf{(a+b)^2=a^2+b^2+2ab} as,

\sf{\sqrt{5+2\sqrt{6}}\:=\: \sqrt{3+2+2\sqrt{3}×\sqrt{2}}}

\sf{\sqrt{\sqrt{(3)^2}+\sqrt{(2)^2}+2\sqrt{3}×\sqrt{2}}}

\sf{\sqrt{(\sqrt{3}+\sqrt{2})^2}}

\sf{\sqrt{3}+\sqrt{2}}

Answered by pradiptadas2007
2

Answer:

√(3+2+2×√3×√2)

=√3+√2

Hope it helps you...

Pls mrk me brainliest...

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