Question

Find the Value of $\sqrt{5x^{8} } - \sqrt{20x^{8} } + \sqrt{45x^{8} }$ ,Where x is the positive real and positive number​

Answer 1

Answer:

2√5 x⁴

As

$\sqrt{5 {x}^{8} } = \sqrt{ {5} } {x}^{4} \\ \sqrt{20 {x}^{8} } = 2\sqrt{ {5} } {x}^{4} \\ \sqrt{45 {x}^{8} } = 3\sqrt{ {5} } {x}^{4}$

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