Question

find the value of
$\sqrt{8} \: upto \: 3 \: decimal \: places$
​

Answer 1

Answer:

2.828

Step-by-step explanation:

Answer 2

$\sf \fbox \red{Question}$

$\sf \: find \: the \: value \: of \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf \sqrt{8} \: upto \: 3 \: decimal \: places$

$\sf \fbox \red{Answer}$

How To find the square root of a non perfect square natural number :

1. Group the digits into pairs

2.find largest number whose square is less or equal to the number then divide and get the remainder.

3. Put a decimal point and place zero and pairing into two.

4. Divide again and write remainder follow this process up to three decimal places.

{refer the image abo

$\sf \red{Ans}→ \sf \sqrt{8} = 2.828$